Firstly, fg(x) could be written as f[g(x)], or in other words, the function f acts on the result of x going through the function g (Bear in mind that I'm using the square brackets only because it's easier to see). Hence, we could write fg(x) as f(x3 + 6). This is the same as writing [(x3 + 6) + 2]/9 because you're applying the function f to (x3 + 6) instead of just x. So this would give a final answer of fg(x) = [(x3 + 6) + 2]/9.