A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.

Using the chain rule, we know that dy/dx = dy/dt . dt/dx Therefore we differentiate both equations with respect to t:dx/dt = -4dy/dt = -2/(t^2)therefore dy/dx = -1/4 . -2/(t^2)dy/dx = 1/(2t^2) ... (we know that t = (3-x)/4 )therefore dy/dx = 8/((3-x)^2)

BA
Answered by Brandon A. Maths tutor

3263 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve has equation y = f(x) and passes through the point (4, 22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7, use integration to find f(x), giving each term in its simplest form


A curve has the equation y = 4x^3 . Differentiate with respect to y.


What is the signed area between the curve y = x^2 - 4 and the x-axis?


using the substitution u=6-x^2 integrate (x^3)/(6-x^2)^1/2 with respect to x, between 1 and 2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning