make x the subject of 5(x-3) = y(4-3x)

step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

Answered by Sofia A. Maths tutor

4421 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find a quarter of the area of a circle with a diameter of 10cm.


15x^2 − 4x + x^2 + 9x − x − 6x^2 =


Rationalise the Denominator: 5+√2/(√3)


Prove that the square of an odd number is always 1 more than a multiple of 4


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences