Solve the Simultaneous equation: 6x+3y=13, 14x-9y=9?

First we need to eliminate one of the Variables, to have an equation dependant on one variable. The coefficient for y in equation two is a third of the coefficient of the y in the second equation. Therefore, time the first equation by three to get 18x+9y=39. Now you can cancel the y out in each equation by adding the two variable together. This gets you 32x=48, from this you get that x=3/2. Now you have the value of one of the variables so you can plug in the value into one of the equations to obtain a value for the other variable. Plugging in value of x into the first question to obtain: 3y+9=13. Tidy up the equation to get 3y=4. From this you obtain that y=4/3. Hence the values for the two variables are: x=3/2, y=4/3

Answered by Matthew M. Maths tutor

2707 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise 5 – 10m


Starting with x^2+2x+1=0 use the method of factorising to solve for x.


How do I work out the area of a quarter circle with radius 6cm?


Solve the following equation: x^2- x - 12 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences