Because there is no unique solution to the problem the goal is to think different ways to approach an issue and ultimately opt for the best one in terms of complexity. There is an example of set of answers that would show creative thinking and good problem solving skills.1) Trivial solution, just make sure that it works by using 2 for loops to try every combination of sums-> O(n^2)2) Improved solution, realise that you can search faster by binary searching the second element of the sum -> O(nlog(n))3) Best solution, make the complexity linear by using two "pointers" to the start and the end of the vector and gradually step back or forward accordingly to the sum.