How do you find the equation of a tangent to a curve at a certain point, from the equation of the curve?

First thing you would do is write down the coordinates where the tangent meets the curve. After that you would differenciate the equation (f(x)) of the curve (do dy/dx) in order to get f'(x).Then you would subsitute in the value of x at the point where the tangent meets the curve into f'(x), which is the differenciated equation, which would give you the gradient of the tangent. after that you know that y = MX + C therefore you can subsitute in the values for y (the y coordinate at the point where the tangent and the curve meet), the M (The gradient of the tangent) and X (the x co-ordinate at the point where the tangent meets the curve). After that, all you have to do is rearange the equation to get C and that will give you the eqution of the tangent to the curve at that point.

Answered by Antoine O. Maths tutor

2972 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Prove the following identity: (1+cos⁡(x)+cos⁡(2x))/(sin⁡(x)+sin⁡(2x) )=cot⁡(x)


In a science experiment a substance is decaying exponentially. Its mass, M grams, at time t minutes is given by M=300e^(-0.05t). Find the time taken for the mass to decrease to half of its original value.


Write 9sin(x) + 12 cos(x) in the form Rsin(x+y) and hence solve 9sin(x) + 12 cos(x) = 3


How would you work out the equation of the normal at a point (2,5) given the equation of a line?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences