A particle P of mass 0.4 kg is moving under the action of a constant force F newtons. Initially the velocity of P is (6i – 27j) m s−1 and 4 s later the velocity of P is (−14i + 21j) m s−1 . Find, in terms of i and j, the acceleration of P.

On the whiteboard I would provide a brief drawing of the particle, and of all the information provided (force applied to P and its before and after velocity) as a visual aid for the student. I would ask/remind the student of the equation for acceleration (= (final velocity - initial velocity)/time), and then prompt them to use the information provided in the question to find values to substitute into the equation. From this we would get acceleration = ((-14i + 21j) - (6i - 27j))/4Step by step I would encourage the student to simplify the equation to make it more manageable i.e. (-14i + 21j - 6i + 27j)/4Then (-20i + 48j)/4From this we can finally reach the answer - 5i + 12j

Answered by Finn W. Maths tutor

6420 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How does Pythagoras Theorem work?


How can I solve equations like 2x + 3 = 8x + 21?


Solve the following simultaneous equations: 2x-3y=16 x+2y=-6


y is proportional to x^2 and that when y = 75, x = 5. Find a formula for y in terms of x and find y when x=3


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences