Sketch the curve with the equation y=x^2 +4x+4, labelling the points where it crosses or touches the axes.

The curve is a quadratic equation because it has a x^2 - as it is positive it will be a u shaped parabola. The equation can be factorised by thinking of two numbers which add to make 4 (the b value) and multiply to make 4 (the c value). This gives (x+2)^2.You make it equal to 0, giving a value of x=-2. This is a repeated root meaning that the trough of the curve will touch the x-axis at -2. The y-intercept can be found by substituting a value of x=0 into the equation. This gives the co-ordinate (0,4). The sketch will be drawn on the whiteboard.

SS
Answered by Sophia S. Maths tutor

4249 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the area bounded by the curve x^2-2x+3 between the limits x=0 and x=1 and the horizontal axis.


The equation of a line is y=e(^2x)-9 and the line has points at (0,a) and (b,0). Find the values of a and b.


differentiate with respect to 'x' : ln(x^2 + 3x + 5)


Differentiate y=x^3*(x^2+1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning