Sketch the curve with the equation y=x^2 +4x+4, labelling the points where it crosses or touches the axes.

The curve is a quadratic equation because it has a x^2 - as it is positive it will be a u shaped parabola. The equation can be factorised by thinking of two numbers which add to make 4 (the b value) and multiply to make 4 (the c value). This gives (x+2)^2.You make it equal to 0, giving a value of x=-2. This is a repeated root meaning that the trough of the curve will touch the x-axis at -2. The y-intercept can be found by substituting a value of x=0 into the equation. This gives the co-ordinate (0,4). The sketch will be drawn on the whiteboard.

SS
Answered by Sophia S. Maths tutor

3906 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

y = 1/x^2, differentiate y (taken from AQA 2018 past paper)


f(x) = sinx. Using differentiation from first principles find the exact value of f' (π/6).


y =(4x)/(x^2+5) (a) Find dy/dx, writing your answer as a single fraction in its simplest form. (b) Hence find the set of values of x for which dy/dx<0


(i) Prove sin(θ)/cos(θ) + cos(θ)/sin(θ) = 2cosec(2θ) , (ii) draw draph of y = 2cosec(2θ) for 0<θ< 360°, (iii) solve to 1 d.p. : sin(θ)/cos(θ) + cos(θ)/sin(θ) = 3.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning