An electron is accelerated through a uniform electric field of strength, E= 20 [N/C]. Determine the speed after the the electron travels 0.5 m from rest.
E=F/Q. F= 20*(1.6910^-19)=3.3810^-18NF=ma m=9.1110-31 kgTherefore, a = 3.71 * 10^12 m/s^2Since v^2= u^2 + 2as and s= 0.5m,Then v=1.9310^6 m/s
LF
Related Physics A Level answers
All answers ▸Calculate the resistance of a uniform wire of diameter 0.5mm, length 2m and resistivity 1.7x10^-8Ωm.
How would you prove the formula for the total capacitance of a system consisting of several capacitors linked in series?
From the definition of the decay constant for nuclear decay, derive the exponential decay equation.
An electron is emitted from a cathode in an electron gun, with a potential difference of 150kV. Find the velocity of the electron after it is accelerated and find the De Broglie wavelength.