Solve the simultaneous equations: y-2x-4=0, 4x^2+y^2+20x=0

Re-arrange y-2x-4=0 to y=2x+4Substitute y=2x+4 into 4x^2+y^2+20x=0 to get 4x^2+(2x+4)^2+20x=0Expand the brackets to get 4x^2+(4x^2+16x+16)+20x=0Simplify to get 8x^2+36x+16=0Divide by 4 to get 2x^2+9x+4=0Factorise to get (2x+1)(x+4)=0Set each bracket to zero so that x= -1/2 or -4Plug these values back into y=2x+4 to get y= 3 or -4

AH
Answered by Andrew H. Maths tutor

7172 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate ln(x)?


Solve the following equation by completing the square: x^2 + 6x + 3 = 0.


Consider a differential equation where dx/dt = -axt. Find an equation for x(t).


Let f(x) = 2x^3 + x^2 - 5x + c. Given that f(1) = 0 find the values of c.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning