Solve the simultaneous equations 3x +y =11 and 2x+y=8

Equation 1: 3x+y= 11, Equation 2: 2x+y=8. You want to find out what x is and what y is.In both equations there is only 1 unit of y therefore it is easiest to rearrange the first equation so that it equals y this will become your equation 3. Equation 3: y=11-3x, Equation 2: 2x+y=8. Substitute equation 3 into equation 2. 2x+ 11-3x= 8 , 11-x=8, x= 11-8, x=3 Substitute x back into equation 3y=11-3x, y= 11-3(3), y=11-9, y=2. Therefore x= 3 and y= 2

Answered by Kathryn M. Maths tutor

3621 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations “x^2+y^2=4” and “x=2-y”. What does this tell us about the circle centred on the origin, with radius 2, and the straight line with y-intercept 2 and gradient -1?


Factorise x^2 - 8x + 12


Expand and Simplify: 16=(x-3)(x+3)


(8/125)^(-2/3)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences