Find the gradient of the tangent to the curve y=4x^2 - 7x at x = 2

First, we differentiate our equation using the power rule:dy/dx = 8x - 7This is the gradient of our tangent, to the original equation, at any point x. So, to calculate the gradient at x = 2, we substitute this value into dy/dx.So, we have: gradient = 8(2) - 7 = 9 as required.

LA
Answered by Luke A. Maths tutor

5040 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y = 15x^3 + 24x^2 + 6 with respect to x.


The equation: x^3 - 12x + 6 has two turning points. Use calculus to find the positions and natures of these turning points.


Find dy/dx for y = x^3*e^x*cos(x)


Let R denote the region bounded by the curve y=x^3 and the lines x=0 and x=4. Find the volume generated when R is rotated 360 degrees about the x axis.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning