Differentiante y = arctan(c)

y = arctan(x)tan(y) = xsec2(y) = dx/dyfrom cos2A + sin2A = 1, we know that 1 + tan2A = sec2A (divide by cos2A), so we substitute in1 + tan2(y) = dx/dyfrom the initial relationship,1 + x2 = dx/dyfinally reciprocate the expression to get1/(1+x2) = dy/dx (Solved)

Answered by Savvas S. Maths tutor

2570 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the equation of the normal line at the point H, where θ= π/6, on the curve with equations x=3sinθ and y=5cosθ


How can the y=sin(x) graph be manipulated?


How do you find the normal to a curve at a given co-ordinate?


For a given function F(x), what does the graph of the function F(x+2) look like in comparrison to F(x)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences