y = arctan(x)tan(y) = xsec2(y) = dx/dyfrom cos2A + sin2A = 1, we know that 1 + tan2A = sec2A (divide by cos2A), so we substitute in1 + tan2(y) = dx/dyfrom the initial relationship,1 + x2 = dx/dyfinally reciprocate the expression to get1/(1+x2) = dy/dx (Solved)