Differentiate with respect to x and write in its simpliest form, Y=(2x-3)/x^2?

Y=(2x-3)/x²

Quotient Rule: dY/dx(u/v)=(u'v-v'u)/v²

dY/dx=(2x²-2x(2x-3))/x⁴

=(6x-2x²)/x⁴    (Collect numerator x terms.)

=(6-2x)/x³         (Cancel the fraction by a factor of x.)

dY/dx=(6-2x)/x³