Magnesium reacts with hydrochloric acid to form a salt. What volume of 0.2dm(-3) HCL is required to react with 4g of Magnesium? Give answer in cm(3).

First draw out the equation. Mg + HCL = MgCl2 + H2Now balance this equation Mg + 2HCl = MgCl2 + H2Next we need to work out the moles of Mg. We know that we have 4g and Mg has a molar mass of 24. Mass/molar mass = moles. So 4/24 = 0.167 moles of Mg. In the equation we can see the ratio of Mg: HCl is 1:2. So we have 0.164 x 2 mol of Hcl = 0.333. To work out volume= mol/ conc. 0.333/0.2 = 1.665. The question asks for this in cm3 so the final answer is 1665 cm3.

Answered by Katie C. Chemistry tutor

4385 Views

See similar Chemistry GCSE tutors

Related Chemistry GCSE answers

All answers ▸

Calculated the Relative Molecular Mass of calcium (II) chloride using the periodic table.


Please describe an Ionic Bond


Explain, in terms of its structure, why graphite is able to be used as a lubricant


Why does iodine have a higher boiling point than chlorine?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences