Assume y = 2x + pi/2,
Since the period of 'tangent' is pi, the general solution of 'y' to valid the equation of tan(y) = SQRT(3) is the form of y = npi+pi/3 where 'n' is any positive or negative integer and zero.
Substitute y back to the equation, it becomes 2x + pi/2 = npi+pi/3.
Simplify this equation in the form of 'x', it becomes: x = 1/2(n*pi - pi/6) where 'n' is any positive or negative integer and zero.