Standard deviation is the spread of data around the mean value. It is useful for evaluating the spread of a selection of data, and is used to compare multiple data sets. Ideally a data set would have a low standard deviation.
For NON-GROUPED DATA
This is the standard deviation for a list of numbers (there are no frequencies)
s2 = (∑ [ x - x̄ ]2)/n
s = Standard deviation
x̄ = the mean of the data set
x = number in the data set
n = the amount of numbers in the data set
∑ = the sum of
Example
Find out the standard deviation of 4, 9, 11, 12, 17, 5, 8, 12, 14
1) Work out n
There are 9 numbers in the data set
n = 9
2) Work out the mean of the data set (the sum of the numbers divided by the amount of numbers)
x̄ = (∑x)/n
x̄ = (4+9+11+12+17+5+8+12+14)/9 = 10.222 (3dp)
3) Work out ∑( x - x̄ )2
Subtract x̄ from each value to get x - x̄
The square the result (to 3dp) to get ( x - x̄ )2
Then add all of the last column together (sum) to get the total (to 3 decimal places) = (∑ [ x - x̄ ]2)
x x- x̄ ( x - x̄ )2
4 -6.222 38.713
9 -1.222 1.493
11 0.778 0.605
12 1.778 3.161
17 6.778 45.941
5 -5.222 27.269
8 -2.222 4.937
12 1.778 3.161
14 3.778 14.273
∑ ( x - x̄ )2 = 139.553
4) Work out the standard deviation
Divide the answer from 3 by the answer from 1
Square root the result (to 3dp)
s2 = (∑ [ x - x̄ ]2)/n
s = √{(∑ [ x - x̄ ]2)/n}
s2 = 139.553/9
s = 3.938 (3dp)
So the standard deviation for this data set it 3.938 (3dp)