(Follow on from previous question) A curve has equation y= x^2+3x+2. Use your previous results to i) find the vertex of the curve ii) find the equation of the line of symmetry of the curve

i) y = x2+3x+2 = (x+3/2)2-1/4Solution for (x+3/2) = 0 is x coordinate, which is x = -3/2Solution for y value is the additional constant, which is y = -1/4Therefore the vertex (minimum point) is (-3/2,-1/4)
ii) The line of symmetry is x = -3/2 (a vertical line that runs through the vertex of the curve)

RI
Answered by Ross I. Maths tutor

2891 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I do this question: A small stone is projected vertically upwards from the point A with speed 11.2 m/s. Find the maximum height above A reached by the stone.


Find the first derivative of the line equation y=x^3 + 4


Differentiate y=x^(-1/2)-x


Find the area enclosed between the curves y = f(x) and y = g(x)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences