(Follow on from previous question) A curve has equation y= x^2+3x+2. Use your previous results to i) find the vertex of the curve ii) find the equation of the line of symmetry of the curve
i) y = x2+3x+2 = (x+3/2)2-1/4Solution for (x+3/2) = 0 is x coordinate, which is x = -3/2Solution for y value is the additional constant, which is y = -1/4Therefore the vertex (minimum point) is (-3/2,-1/4)
ii) The line of symmetry is x = -3/2 (a vertical line that runs through the vertex of the curve)
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