Solve the simultaneous equations: 3x + y = 19 and x - 2y = -3

First rearrange x - 2y = -3 by adding 2y to each side to give x = -3 + 2ySubstitute this into the first eq. to give 3(-3 +2y) + y = 19Expand brackets first: -9 + 6y + y = 19Rearrange and simplify by collecting the y terms and adding 9 to both sides, so terms of y are on one side and numbers on the other: 7y = 28Divide both sides by 7 to get y = 28/7 = 4Substitute y = 4 into the equation for x to find the value of x: x = -3 + 2y = -3 + (2*4) = -3 + 8 = 5x=5, y = 4

Answered by Jessica M. Maths tutor

4484 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve simultaneous equations?


find the values of x when 3x^2 - 6x - 9


Draw the graph y=4x+2


Jill and four friends go camping together for 5 days. The friends share the cost of the trip equally. These costs are: £120 for fuel, £58 for food, £100 for equipment and £207 for activities. How much does Jill have to pay for her share of the costs?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences