Differentiate dy/dx ((2x^3)+(x^2)-(4x)+7)
Differentiate each term in the equation separately then put then put the differentiated equation back together.First we start with (2x3):2 x 3 = 6 and 3-1=2 so we get the differentiated term of 6x2then we move onto the next term x2 which is differentiated to 2xnext we get -4x to -4and finally when we differentiate a number on its own it goes to 0 so our final term of 7 disappears. When we put all the differentiated terms back together we get our final result of dy/dx (2x3 + x2 -4x + 7) = 6x2 + 2x -4
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