y = x^3 ln x. Find dy/dx

dy/dx = u.dv/dx + v.du/dxu = x3, v = ln xdu/dx = 3x2, dv/dx = 1/xdy/dx = 3x2 lnx + x2

Answered by Tarun U. Maths tutor

12290 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate the following between 0 and 1: (x + 2)^3 dx


Curve C has equation 4x^2- y^3 - 4xy +2^y = 0 , point P (-2, 4) lies on C, find dy/dx at the point P


A curve has the equation y = (1/3)x^3 + 4x^2 + 12x +3. Find the coordinates of each turning point and determine their nature.


What is the "chain rule"?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences