Solve:

x2 + y2 = 25 y – 3x = 13 Rearrange the second equation: y = 13 + 3x Substitute the rearranged question in the first equation: x2 + (13 + 3x)2 = 25 Solve: x2 + 169 + 9x2 + 78x - 25 = 0 10x2 + 78x + 144 = 0 5x2 + 39x + 72 = 0 x = (-39 +- /1521-1440)/10 x = (-39 +-9)/10 x = -4.8, x = -3 Subsitute these two values in the rearranged equation: x = -4.8 --> y = 13 + 3*(-4.8) = -1.4 x = -3 --> y = 13 + 3*(-3) = 4

Answered by Bandana J. Maths tutor

2571 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand (t+5)(t-2)


Solve this pair of simultaneous equations: 3x + y= 7 and 3x - y = 5


A rectangle has an area of 20cm^2. Its length and width are each enlarged by scale factor 3. What is the area of the enlarged rectangle?


Find an equation of the line which passes through the point (4,-7) and has slope 3.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences