What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2

dy/dx=3x^2+6xx=2m=3(2)^2+6(2)=24at x=2 y=22(2,22)y-22=24(x-2)y-22=24x-48y=24x-26

KH
Answered by Kieran H. Maths tutor

3955 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the values of x and y for which dy/dx = 0 in y= x^3 - 4x^2 - 3x +2


Which value of x gives the greatest value of "-x^2+8x-6"


Given y = 3x^(1/2) - 6x + 4, x > 0. 1) Find the integral of y with respect to x, simplifying each term. 2) Differentiate the equation for y with respect to x.


differentiate parametrically y=3t+4 and x=2t^2 +3t-5


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning