What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2

dy/dx=3x^2+6xx=2m=3(2)^2+6(2)=24at x=2 y=22(2,22)y-22=24(x-2)y-22=24x-48y=24x-26

KH
Answered by Kieran H. Maths tutor

4040 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate 3x^(3/4)


Express square root of 48 in the form n x square root of 3 , where n is an integer


Where does integration by parts come from?


Given that 9 sin^2y-2 sin y cos y=8 show that (tany - 4)(tany + 2)= 0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning