What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2

dy/dx=3x^2+6xx=2m=3(2)^2+6(2)=24at x=2 y=22(2,22)y-22=24(x-2)y-22=24x-48y=24x-26

Answered by Kieran H. Maths tutor

3314 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

differentiate ln( x^2 )


Given the parametric equations x = t^2 and y = 2t -1 find dy/dx


Sketch the graph of x^2+y^2-6x-4y=23


Express [1+4(square root)7] /[ 5+ 2(square root)7] in the form m + n (square root)7 , where m and n are integers.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences