equation(1) h = 3t^2 a) find h when t=5 b)find t when h=108

for part AYou would but the t2 into brackets , then substitute t=5 to get h=3(52) using BIDMAS do the 52 = 25 so that h=3(25) so you end up with h=75
for part B first you would rearrange the equation to make t the subject (t on its own on one side) h/3=t2 then square root h/3sqrt{h/3}=t Then finally you substitute In h=108 sqrt{108/3}=tsqrt(3)=t

Answered by Danielle N. Maths tutor

4206 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Can two shelves of 0.72 meters long each store 50 30mm wide textbooks?


How do I solve inequalities when they're not linear?


Use these 2 simultaneous equations to find x & y: 5y+21=9x and 6x+7y=45


What is £23 increased by 4%?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences