equation(1) h = 3t^2 a) find h when t=5 b)find t when h=108

for part AYou would but the t2 into brackets , then substitute t=5 to get h=3(52) using BIDMAS do the 52 = 25 so that h=3(25) so you end up with h=75
for part B first you would rearrange the equation to make t the subject (t on its own on one side) h/3=t2 then square root h/3sqrt{h/3}=t Then finally you substitute In h=108 sqrt{108/3}=tsqrt(3)=t

Answered by Danielle N. Maths tutor

4205 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 3x + 2y = 4, 4x + 5y = 17


Rearrange the following equation to make 'm' the subject: 4 (m - 2) = t (5m + 3) [4 marks]


A) Multiply out 6(n - 2). B) Factorise psquared - 5p


How to find surface area and volume of a cone


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences