Solve the simultaneous equations: 1) 3x+5y=14 and 2) -3y+10=x
- Multiple the second equation through by 3 so that the x is multiplied by the same number in both equations. -> -9y + 30 = 3x
2) Rearrange the equation so that the x and y are both on the same side.
-> 3x + 9y = 30
3) Minus the first equation away from the second to remove the x.
-> 3x + 9y = 30- 3x + 5y = 14
= 4y = 16
4) Now divide both sides of the remaining equation to work out y.
-> y=4
5) Now replace y with 4 in either equation to find x. (For this example I will use the first equation)
-> 3x + 5(4) = 14
3x + 20 = 14
3x = -6
x = -2
so... y=4 and x=-2
GS
Related Maths GCSE answers
All answers ▸Solve this simultaneous equation for x: 3x + y = 10, x + y = 4
How many centimeters are there in 6.8 meters?
X=4a+3b, If a is a two digit cube number and b is a two digit square number then what is the lowest possible value for X?
A 4 digit number is picked. It's second digit is a prime number, it must be even and it must be greater than 5000. How many possible numbers can be picked?