Solve the simultaneous equations: 1) 3x+5y=14 and 2) -3y+10=x

  1. Multiple the second equation through by 3 so that the x is multiplied by the same number in both equations. -> -9y + 30 = 3x
    2) Rearrange the equation so that the x and y are both on the same side.
    -> 3x + 9y = 30
    3) Minus the first equation away from the second to remove the x.
    -> 3x + 9y = 30- 3x + 5y = 14
    = 4y = 16
    4) Now divide both sides of the remaining equation to work out y.
    -> y=4
    5) Now replace y with 4 in either equation to find x. (For this example I will use the first equation)
    -> 3x + 5(4) = 14
    3x + 20 = 14
    3x = -6
    x = -2
    so... y=4 and x=-2

Answered by Gabrielle S. Maths tutor

3563 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the inequality 6y + 5 > 8


The graph of y = x^2 + 4x - 3 (Graph A) is translated by the vector (3 | 2), find the equation of the new graph (Graph B)


What is BODMAS?


a.) simplify and expand (x+3)(2x+5) b.) differentiate (x+3)(2x+5) c.) where does this function intercept the x and y axis? d.) does this function have any turning points? if so where?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences