Solve the simultaneous equations: x^2+y^2=36 ; x=2y+6

Substitute x in terms of y into the first equation:

(2y+6)2+y2=36

Use FOIL to expand the brackets

4y2+24y+36+y2=36  =>   5y2+24y=0

y(5y+24)=0  =>  y=0   or    y=(-24)/5

Substitute these values of y into the second equation to find x

when y=0, x=2*0+6  =>  x=6

when y=(-24)/5,  x=2*(-24)/5+6  =>  x=-3.6

DB
Answered by Daniel B. Maths tutor

30315 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A right angle triangle has a base of √8 and a height of (√10+3). Show that the area is equal to 2√5+3√2.


You have a bag of 60 coloured marbles. 1/10 are red, 3/5 are blue, and the rest are green. How many green ones are there?


Show me why the product of a squared and a cubed is a to the power of 5.


how do i calcualte the length of an unknown side of a right angled triangle


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences