Consider the closed curve between 0 <= theta < 2pi given by r(theta) = 6 + alpha sin theta, where alpha is some real constant strictly between 0 and 6. The area in this closed curve is 97pi/2. Calculate the value of alpha.

Student uses the definition of area [A = 1/2 integral r(theta)^2 d theta], and proceeds using standard integration techniques to give a quadratic solvable for alpha. [alpha^2 = 25] Thus, alpha = 5.

Answered by Graham C. Maths tutor

3206 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I add up the integers from 1 to 1000 without going insane?


How do you integrate the natural logarithm ln(x)?


Find the value of the discriminant of x2 + 6x + 11


How do you differentiate using the chain rule?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences