Solve 3x^2+7x-13=7 to find x.

Firstly, you need to get the equation to equal zero, so that you can use the quadratic formula to solve. Therefore you subtract 7 from both sides, meaning the equation becomes: 3x^2+7x-20=0. Recall the quadratic formula: x =( -b +/- sqr root(b^2-4ac))/2a, when the equation is ax^2+bx+c, this means that a = 3, b = 7 and c = -20. Subbing this into the formula you get that x = -4 and x = 1.67 (to 2 dp).

Answered by Ellie M. Maths tutor

3166 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the following pair of simultaneous equations; 10x+4y=15, 2x+y=7


can you show me how to solve simultaneous equations?


What is the point of intersection of two lines, and how would I find it?


Solve 7x - 14 = 4x + 7


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences