An electron is emitted from a cathode in an electron gun, with a potential difference of 150kV. Find the velocity of the electron after it is accelerated and find the De Broglie wavelength.
V=J/C1.602×10^-19 ×150×10^3=1/2×m×v^2
v=(2×1.602×10^-19×150×10^3/9.11×10^-31)^1/2v=2.29×10^8 m/sλ=h/pλ=6.63×10^-34/2.29×10^8 × 9.11×10^-31λ=3.17×10^-12
AC
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