f(x)=12x^2e^2x - 14, find the x-coordinates of the turning points.

f(x)=(12x^2)(e^2x) - 14, so using the chain rule f'(x)=(24x)(e^2x) + (12x^2)(2e^2x).To find the turning points set f'(x)=0, so (24x)(e^2x) + (24x^2)(e^2x) = 0. Thus (24xe^2x)(1+x)=0. Thus x=0 or x=-1.

Answered by Charlotte H. Maths tutor

2683 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the first three terms in the expansion of (4-x)^(-1/2) in ascending powers of x.


A stone is thrown from a bridge 10m above water at 30ms^-1 30 degrees above the horizontal. How long does the stone take to strike the water? What is its horizontal displacement at this time?


How do you find the turning points of a curve described by the equation y(x)?


How do you integrate 3x^2 - 6x + 5 (wrt x)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences