AC and DB must be perpendicular therefore m1m2 = -1. (we can work out the gradient of DB)-4m2 = -1 -----> m2 = 1/4The equation of a line is y-y1=m(x-x1) (sub in x, y and gradient values)y - 7 = 1/4(x-10) (multiply by 4 to get rid of fractions)4y - 28 = x -10 (make = to 0)x - 4y + 18 = 0