An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?

F=BQv so B=F/Qv (Q is the charge of an electron, 1.6 x10-19 C) so B=4.32 x10-16 / (1.6 x10-19 x 500) = 5.4 T

CJ
Answered by Christian J. Physics tutor

2033 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Why is Kinetic Energy mv^2/2?


If f(x)= ln(x^2)-4, give f^-1(x)


How should I structure my experiment report?


A ball is initially at rest and is dropped from a height of 10m. Calculate the velocity of the ball when it reaches the ground


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning