An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?

F=BQv so B=F/Qv (Q is the charge of an electron, 1.6 x10-19 C) so B=4.32 x10-16 / (1.6 x10-19 x 500) = 5.4 T

CJ
Answered by Christian J. Physics tutor

1885 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

How does the photoelectric effect (gold leaf experiment) demonstrate the particle nature of light?


What Newton’s third law of motion?


Show that a pendulum undergoes simple harmonic motion (SHM). State your assumptions. The pendulum is made up of a light inextensible string, attached to a ceiling at one end and with a particle of mass m attached to the other end.


Electrons moving in a beam have the same de Broglie wavelength as protons moving in a separate beam. The proton beam moves at a speed of 3.1 x 10^4 m/s. What is the speed of the electrons?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning