An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?

F=BQv so B=F/Qv (Q is the charge of an electron, 1.6 x10-19 C) so B=4.32 x10-16 / (1.6 x10-19 x 500) = 5.4 T

CJ
Answered by Christian J. Physics tutor

1851 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Why does an electric drill heat up when passing through metal compared to in thin air?


What does a stress-strain curve for a metal look like and what does each part mean?


State the principle of superposition of waves and illustrate it schematically.


There is a train A. On the roof of A is another frictionless train B of mass Mb. A mass Mc hangs off the front of A and is attached to the front of B by rope and frictionless pulley. How fast should A accelerate so that B wont fall off the roof of A.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning