Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

TB
Answered by Tamim B. Maths tutor

3773 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is a vector?


How do I find the equation of a line connecting points a(p,q) and b(r,s)?


Why is the area of a triangle 1/2 * b * h?


What is rationalising a fraction?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning