Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

TB
Answered by Tamim B. Maths tutor

3476 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Sketch and label the graph of y=x^2 -5x+6


Solve the equation 4(3x-2)=2x-5


P has coordinates (0, -1) and Q has coordinates (4, 1). a) Find the equation of line PQ. b) P and Q are two vertices of rectangle PQRS. Find the equation of line QR.


Simplyfy, ((x-2)(x^2+5x+6)-(2x^2+10x+12))/(x^2+x-2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning