Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

Answered by Tamim B. Maths tutor

2657 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the value(s) of x which satisfies the equation 3x^2 + 6x + 3 = 0


How to expand and simplify expressions


What is the fraction of blue beads?


Solve 2x + 7 = 13


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences