Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

Answered by Tamim B. Maths tutor

2926 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2 + 7x + 10 = 0


Find the roots of the following equation 2x^2-11x+14=0


Factorise x^2 - 8x - 20


Solve "x^2 - 12x - 45 = 0" by completing the square


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences