If a car drives at 5 ms^-1 for 10 seconds and then 6 ms^-1 for 5 seconds, how far has it travelled in total?
The equation used here is speed = distance / time (s=d/t). Firstly the 30 ms^-1. Rearrange the equation to find distance (st=d). 5ms^-1 x 10s = 50m. The second stint is 6ms^-1 x 5s = 30m. This makes the total distance as 30m + 50m = 80m.
MP
Related Physics GCSE answers
All answers ▸How do current and voltage vary in series and parallel circuits, respectively?
A box is at rest on a slope with an angle ϴ. Find an expression for the static friction coefficient, μ, of the box.
A car accelerates (at a constant acceleration) from a velocity of 25m/s to 34m/s in 6s. Calculate the cars acceleration.
Explain why an ice cube submerged in a drink melts faster than an ice cube on a kitchen surface (the drink, surface and room temperature are all equal). (3 marks)