The circle C has centre (3, 1) and passes through the point P(8, 3). (a) Find an equation for C. (b) Find an equation for the tangent to C at P, giving your answer in the form ax + by + c = 0 , where a, b and c are integers.

A)1) Draw a diagram of the circle displaying the centre and perimeter points along with their respective co-ordinates.2) Write down the equation for a circle labelling the centre and perimeter points. 3) Input values and solve for r. * Remember to square root your answerB)1)Add the tangential line to the initial diagram making sure that it passes through the point P. 2) Notice that the tangential line is perpendicular to the radius and thus draw in a right-angle symbol to ensure you do not forget. 3) Determine the gradient of the radius using the gradient of a line equation. 4) Seeing as the tangential line is perpendicular ( at right-angles to the radius), use the following equation: m2= -1/m1m2-gradient of perpendicular tangent m1-gradient of radius 5) Use the following equation to find the point at which the tangential line crosses the y axis:y-y1= m(x-x1) where y1 and x1 are two co-ordinates on this line. 6) Finally, re-arrange the equation for zero.