A particle of mass m is placed on an slope with an incline 30 degrees. Once released it accelerates down the line of greatest slope at 2 m s^-2. What is the coefficient of friction between the particle and the slope?

Resolve forces perpendicular to the slope. No acceleration in this direction hence resultant force in this direction must equal zero:R = mg * cos(30) Apply Newtons second law in the direction parallel to the slope:F = m * amg sin(30) - μR = maSubstitute in R = mg * cos(30) :mg sin(30) - μmg * cos(30) = macancel m:g sin(30) - μg * cos(30) = arearrange for μμ=(gsin(30) - a)/(gcos(30)) = (9.8sin(30)-2)/(9.8cos(30)) =0.342

Answered by Daniel H. Maths tutor

3262 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the exact solutions for 4 − x^2 = |2x − 1|


Find the turning points and their nature of the graph y = x^3/3 - 7x^2/2 + 12x + 4


What is the coefficient of x^4 in the expansion of (x+3)^7


How do I solve this inequality: x^2>2x ?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences