First, imagine that f(x) is written as y:
y = (3x -6)/2
swap the variables over so you write y as x and x as y:
x = (3y - 6)/2
Next, solve for x (try and get the y on its own on the right hand side)
2x = 3y - 6
2x + 6 = 3y
(2x + 6)/3 = y
Finally, swap the x and y back over to receive your answer!
f(x)' = (2x + 6)/3
where f(x)' is the inverse of f(x)