Energy
GPE of the ball on the bridge: MGH = 1 * 9.81 * 20 =196 J
energy lost to drag = F * D = 2 * 20 = 40 J
Velocity of the ball just before impact =sqr(2*(196-40)/1) =17.66 m/s
Velocity of the ball just after impact = 17.660.5 = 8.83 m/s
Kinetic energy just after impact 0.5 * 1 * 8.83^2 =39 J
Equation for final height (using energy)
KE = Drag energy + GPE
39 = 2H + 19.81H
H=3.30m
1724 Views
See similar Further Mathematics A Level tutors