Solve the following simultaneous equations: x+y=9; x-2y+1=1.

Step 1: x+y=7 can be rearranged as: x= 9 - y.Step 2: We substitute the expression of x in the second equation: 9 - y - 2y + 1 = 1Step 3: We calculate the value of y. 9 + 1 - 1- 3y=0. It is equivalent with: 9 - 3y = 0. So, 9=3y. y=9/3. y=3Step 4: We calculate x. x=9-y ; x= 9-3; x=6Step 5: Checking the values in the given equations. 6 + 3 = 9 (TRUE) 9 - 3 - 6 +1 = 1 ; 1=1 (TRUE)Step 6: x=6 ; y=3

Answered by Daniel T. Maths tutor

3425 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A* grade question: ((2x+3)/(x-4))-((2x-8)/(2x+1))=1 solve for X


Solve the quadratic equation: x^2 - 2x - 15 = 0


how do you factorise a quadratic where there is a number in front of the x squared?


How do i find 30% of 70?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences