Express (4x)/(x^2-9) - (2)/(x+3) as a single fraction in its simplest form.

First we must expand the demoninator to; (x+3)(x-3)Then we can multiply the left hand fraction on top and bottom by (x-3) to get a common demoninatorthis gives us; (4x)/((x+3)(x-3)) - ((2)(x-3))/((x+3)(x-3))simplyfy the top to get; (2x+6)/((x+3)(x-3))the numerator then can be expanded to give; (2(x+3))/((x+3)(x-3))The (x+3) cancels on top and bottom to give us the final answer; 2/(x-3)

Answered by Eddie E. Maths tutor

3502 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you do algebraic long division?


Using partial fractions find the integral of (15-17x)/((2+x) (1-3x)^2 )


How to differentiate with respect to x, xsin2x.


Solve x^2 + 8x +3 = 0 by completing the square.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences