Given two functions x = at^3 and y = 4a, find dy/dx

Solution: Parametric Differentiation with utilisation of Chain Rule.
By the chain rule: dy/dx = dy/dt * dt/dx
Note: dt/dx = 1 / (dx/dt)
So dy/dt = 0, dx/dt = 3at^2
So dy/dx = 0 * 1/(3at^2) and hence dy/dx = 0.

MP
Answered by Michele P. Maths tutor

3657 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

y =(4x)/(x^2+5) (a) Find dy/dx, writing your answer as a single fraction in its simplest form. (b) Hence find the set of values of x for which dy/dx<0


Write down the values of (1) loga(a) and (2) loga(a^3) [(1) log base a, of a (2) log base a of (a^3)]


Find the equation of a Circle with centre (2,9) and radius 4.


Express 9^(3x+)1 in the form 3^y giving y in the form of ax+b where a and b are constants.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning