Propane and Chlorine react in the presence of UV light to give 2-chloropropane and HCl. Estimate the enthalpy change of this reaction using the following bond enthaplies (KJ/mol) : C-H=+413, Cl-Cl=+243, C-Cl=+346 and H-Cl=+432.

  1. Write equation, ensuring both sides are balanced.CH3CH2CH3 + Cl2 → CH3CH(Cl)CH3 + HCl (2.) Draw structural formula of all reactants and products. (3.) Count the number of, and which types of bonds are present on both sides. Use the bond enthalpies in the question to total up both sides: Reactants: 8(C-H) = 8 * 413, 2(C-C), 1(Cl-Cl) = 243. Products: 7(C-H) = 7 * 413, 2(C-C), 1(C-Cl) = 346, 1(H-Cl) = 432. The bond enthalpy for (C-C) is not given in the question but we can cancel out it out because there are 2(C-C) on each side. Therefore; Reactants = 3547 KJ/mol and Products = 3669 KJ/mol (4.) Use formula Products - Reactants to get answer of +122KJ/mol. Remember the + sign!
Answered by Jasmine W. Chemistry tutor

29480 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

What is the difference between a heterogeneous catalyst and a homogeneous catalyst?


What affects the boiling point of an alkane and why?


i) Write a full balanced equation for (a) the complete combustion of glucose and (b) the incomplete combustion of glucose. ii) Following from part i) suggest a reason (and explain) the difference with the product in reaction (a) and that of reaction (b).


Explain why benzene requires use of a halogen carrier catalyst to react with bromine while phenol does not.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences