Solve, by method of substitution, the simultaneous equations: 5x+y=22 2x+y=10

Solve by substitution:5x + y = 22 (1)2x + y = 10 (2)
First let us label the equations 1 and 2. In order to solve this set of equations we need to rearrange one of the equations so that we have one of the variables (x or y) equal to some expression, or in other words we need to make one of the variable the subject.
I am going to make y the subject in equation (1).
5x + y = 22 -5 -5 (we subtract 5 from both sides)
y= 22 -5x I'll call this equation (3).
So now I substitute (3) into (2) to get:
2x + (22 -5x) = 10
Rearrange to make x the subject:
22 -3x =103x = 12x = 4
Now we sub x=4 into equation (1).
5(4) + y = 2220 + y = 22y = 2
Answer x=4 y=2



AW
Answered by Amy W. Maths tutor

5139 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How to solve an equation when the variable is in the denominator?


I'm struggling with quadratic equations


Solve the following to find x. x^2 +3x -10 =0


How do I solve simultaneous equations?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning