Find ∫ (2x^5 - 1/(4x^3)-5) dx. giving each term in its simplest form.

with integration you need to increase the power and divide through by the new power for each term in the equation.2x5 goes to 2x6/6 = x6/3-1/(4x3) is equal to -x-3/4 which then goes to -x-2/4/-2 = x-2/8 = 1/8x2-5 goes to -5xwith integration a constant is also added to the end. this is due to the constant disappeareing during differentiation which is the reverse of integration.so the final solution is :x6/3 + 1/8x2 - 5x + c

Answered by Kieran Y. Maths tutor

4941 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you find the gradient of a line at a certain point when f(x) is in the form of a fraction, where both the numerator and denominator are functions of x?


Given that x = ln(sec(2y)) find dy/dx


Explain why for any constant a, if y = a^x then dy/dx = a^x(ln(a))


Find the turning point of the function y=f(x)=x^2+4x+4 and state wether it is a minimum or maximum value.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy
Cookie Preferences