In a right angle triangle (where angle ABC is 90 degrees), you are given that angle /_ ACB is 14 degrees and length "AB" is 4. Find the length of "BC".
Using SOH CAH TOA, and labelling each side of the triangle, we see that we are using "TOA". We have the following: tan(14)=4/"BC". Rearranging for "BC", we get the following: "BC" = 4/tan(14), which we calculate to be "BC"= 16.043.
AW
Related Maths GCSE answers
All answers ▸Expand the following brackets, (6x^2-4)(2x+3)
Expand (2x-1)(x+3)
The equation of the line L1 is y=4x–8. The equation of the line L2 is 3y–12x+4=0. Show that L1 and L2 are parallel.
How do I find the roots and and coordinates of the vertex of the graph y = 2x^2 + 4x - 8 ?