Differentiate y = (x^2 + 1)^1/3
Use the chain rule to do this. First set u= x^2 + 1. We chose u to be this because u1/3 is much simpler to differentiate. Then find du/dx = 2x. Now find dy/du = 1/3 * u-2/3 = 1/3 * (x2 +1)-2/3. Now by the chain rule, dy/dx = dy/du * du/dx. Therefore dy/ dx = 2x * (1/3 * (x2 +1)-2/3 )= 2x/3 * (x2+1)-2/3
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