f(x) = e^(sin2x) , 0 ≤ x ≤ pi (a). Use calculus to find the coordinates of the turning points on the graph of y = f(x)
First, understand the concept of a turning point (zero gradient, implying first derivative is zero at the turning point)How do we differentiate exponentials ( if f(x) = e^g(x) then f'(x) = g'(x)*e^g(x) ) Okay, now how do we differentiate (sin2x) (=g(x) in this example)Chain rule & recap how to differentiate trig (we require familiarity with d(sinx)/dx = cosx)Figure out f'(x) and then set to equal zeroSolve equation to find coordinates of turning pointsOf course, use whiteboard and step by step lines of working to guide to answer
MW
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