Solve the simultaneous equations: 2x+5y=25, x=y+2

using our second equation, we can see that x=y+2. Therefore we can sub x into the first equation. This will give us 2*(y+2)+5y=25. We can go ahead and expand the brackets, which gives us 2y+4+5y=25. We can combine the y terms which gives 7y+4=25. We can take 4 away from both sides with gives 7y=21, and divide both sides by 7 so y=3. We can sub 3 into y in the original equation, to give that x=5.

LW
Answered by Louis W. Maths tutor

3999 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise: x^2+2x-3


Find f^-1(x) for the following equation: f(x) = (12+x)/3


A and B are on the line 3x+2y=6. At A x=0, what is y? At B y=0, what is x?


write 2/(3+root(5)) in the form a + b*root(5), where a and b are rational numbers.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning