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A curve has equation 2(x^2)+3x+10. What is the gradient of the curve at x=3

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How do you do integration by parts?

A curve is defined by parametric equations: x = t^(2) + 2, and y = t(4-t^(2)). Find dy/dx in terms of t, hence, define the gradient of the curve at the point where t = 2.

A curve is defined with the following parameters; x = 3 - 4t , y = 1 + 2/t . Find dy/dx in terms of x and y.

express x^2-4x+9 in the form (x-q)^2+y

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