(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60

AE

Related Maths GCSE answers

All answers ▸

Solve these simultaneous equations: 3y + x = 18 and x - 4y = -10.


Show that ((sqrt(18)+sqrt(2))^2)/(sqrt(8)-2) can be written in the form a(b + 2) where a and b are integers.


If a=2 and b=3 , find the value of 2(a−b)+3(a+b)


Find the coordinates of the point where lines 3x+5=y and 6y+x=11 intersect